A

Step 1: Analyze the forces acting on the object during ascent. The net force during ascent is:
\[ F_{net} = T - mg - F_{air} \]
Where:
- T = tension (thrust or initial velocity force)
- mg = weight of the object (where m is mass and g is acceleration due to gravity)
- F_{air} = constant air resistance

Step 2: During ascent, the object experiences negative acceleration (deceleration). Thus, the time of ascent \( t_a \) can be derived from kinematic equations considering the forces.

Step 3: For descent, the net force changes as the thrust is no longer acting, leading to a greater effective downward force due to gravity and air resistance.
\[ F_{net} = mg + F_{air} \]

Step 4: Derive the time of descent \( t_d \) using a similar approach used for ascent.

Step 5: The ratio of time of ascent to time of descent will end up relating to the acceleration due to gravity, resistance forces, and mass. After analyzing the ratios from the resultant equations derived in previous steps, we find:
\[ \frac{t_a}{t_d} = 1:1 \]

Step 6: Therefore, the final ratio of ascent to descent time is \( 1:1 \) because both times are affected proportionately by air resistance with equalizing mass and gravity. Hence, the correct answer is Option A.